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IB Biology D4.3: Climate change worked solutions

Worked solutions to every practice question in D4.3: Climate change of Photon Biology: Study Guide for the IB Diploma (SL & HL). Try each question, then compare your working with the full solution.

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Basic practice

Question A1

[1 mark]
Which statement describes how greenhouse gases warm the Earth? (A) They absorb long-wave radiation emitted by the surface and re-emit some of it downwards. (B) They reflect short-wave radiation from the Sun back down to the surface. (C) They convert short-wave radiation into long-wave radiation high in the atmosphere. (D) They thin the ozone layer, so more ultraviolet radiation reaches the surface.
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Greenhouse gases absorb the long-wave (infrared) radiation that the warmed surface emits and re-emit some of it towards the surface, so heat is retained (A). They do not reflect sunlight (B), do not convert wavelengths (C), and the ozone layer is a different issue (D).

Final answer

A

Question A2

[1 mark]
Which change would most reduce the rate at which atmospheric carbon dioxide is rising? (A) Replacing coal-fired power stations with wind turbines. (B) Draining peatland for crop farming. (C) Clearing forest to make cattle pasture. (D) Burning crop waste in the field after harvest.
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Wind turbines supply energy without burning fossil fuel, so less \ce{CO2} is released (A). Draining peat, clearing forest and burning waste all release carbon or remove uptake.

Final answer

A

Question A3

[1 mark]
Which conditions favour the formation of peat? (A) Warm, well-drained, alkaline soil (B) Waterlogged, oxygen-poor, acidic soil (C) Dry, well-aerated, acidic soil (D) Waterlogged, oxygen-rich, alkaline soil
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Peat needs waterlogged soil with little oxygen and acidity, so decomposers are inhibited and dead plant matter stays partly decomposed (B). Oxygen-rich, drained or alkaline conditions allow decomposition.

Final answer

B

Question A4

[1 mark]
Which change is an example of positive feedback in global warming? (A) Warmer air lets forests grow farther north and take up more carbon dioxide. (B) Melting snow exposes dark soil that absorbs more sunlight and causes more melting. (C) Higher sea level floods coastal wetlands. (D) Warmer seas produce more cloud that reflects more sunlight.
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In B the effect of melting (darker surface, more absorption) strengthens the warming that caused it, so it is positive feedback. A and D reduce warming (negative feedback) and C is a consequence with no return to warming.

Final answer

B

Question A5

[1 mark]
A warm, stable layer of surface water forms across part of an ocean. What is the most likely result? (A) More upwelling and higher primary production. (B) Less upwelling and lower primary production. (C) More dissolved oxygen in the deep water. (D) Faster phytoplankton growth because the water is warmer.
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A stable warm layer mixes poorly with the cold, nutrient-rich water below, so less upwelling brings fewer nutrients to the surface and phytoplankton production falls (B).

Final answer

B

Question A6

[1 mark]
Surveys of a mountain butterfly over 40 years show that both its lower and its upper altitude limits have risen. What is the most likely explanation? (A) Temperatures at the old lower limit now exceed what it tolerates, so its suitable zone has moved upslope. (B) Its predators have moved to lower altitudes. (C) Higher carbon dioxide has made the mountain soil more fertile. (D) The mountain has been uplifted by tectonic movement.
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As the climate warms the temperature zone that suits the species shifts upslope, so both limits rise (A). The other options do not follow from the data.

Final answer

A

Question A7

[1 mark]
What directly causes coral bleaching? (A) Corals expel their symbiotic algae when the water stays too warm. (B) Corals dissolve in acidic water. (C) Algae overgrow the coral and block its light. (D) Corals deposit too much calcium carbonate.
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Prolonged warm water stresses the coral, which expels its zooxanthellae. The coral then lacks the algae and turns white (A).

Final answer

A

Question A8

HL[1 mark]
Which observation is an example of a phenological change linked to warming? (A) A bird species has moved its range towards the pole. (B) Oak trees now open their leaves earlier in spring than in 1980. (C) A frog population has become darker in colour. (D) A snail population has evolved a thicker shell.
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Phenology concerns the timing of seasonal events, such as leaf opening (B). Range shift, colour change and shell thickness are not timing.

Final answer

B

Question A9

[3 marks]
A country records its annual fossil-fuel \ce{CO2} emissions.\begin{array}{lcccc}\hline \text{Year}&\text{1990}&\text{2000}&\text{2010}&\text{2020}\\ \hline \text{Emissions / Gt }\ce{CO2}\text{ per year}&\text{4.0}&\text{4.4}&\text{5.2}&\text{5.6}\\ \hline\end{array} (a) Calculate the percentage increase in emissions from 1990 to 2020. [2] (b) State the decade in which the increase was largest. [1]
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(a) Increase =5.6-4.0=1.6 Gt (1); 1.6/4.0\times100=40\% (1). (b) The changes are 0.4, 0.8 and 0.4 Gt, so 2000 to 2010 (1).

Final answer

(a) 40 %. (b) 2000 to 2010.

Question A10

[3 marks]
Burning coal in a power station adds a gas to the atmosphere. (a) Outline how this can raise the global mean temperature. [3]
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(a) Any three: burning releases carbon dioxide, a greenhouse gas (1); short-wave radiation from the Sun reaches the surface and the surface emits long-wave radiation (1); carbon dioxide absorbs this long-wave radiation (1); it re-emits some of it back towards the surface, so heat is retained and the temperature rises (1).

Final answer

Releases \ce{CO2}; absorbs long-wave radiation from the Earth; re-emits it, so heat is retained.

Tutorial practice

Question B1

[4 marks]
Many power stations burn fossil fuel. (a) Explain how burning fossil fuels leads to an increase in the global mean temperature. [4]
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(a) Any four: fossil fuel combustion releases carbon dioxide (1); carbon dioxide is a greenhouse gas whose concentration therefore rises (1); short-wave radiation from the Sun passes through the atmosphere and warms the surface (1); the surface emits long-wave (infrared) radiation (1); the extra gas absorbs more of this long-wave radiation (1); it re-emits some towards the surface, so more heat is retained (1); the enhanced greenhouse effect raises temperature (1).

Final answer

Release of \ce{CO2}; greenhouse gas; surface emits long-wave radiation; absorbed and re-emitted; heat retained; temperature rises.

Question B2

[5 marks]
Peatlands cover a small fraction of the land but hold a very large store of carbon. (a) Describe how peat forms. [3] (b) Explain why draining a peatland increases carbon dioxide emissions. [2]
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(a) The soil is waterlogged, so there is little oxygen (1); the conditions are acidic, so decomposers are inhibited (1); dead plant matter is only partly decomposed and accumulates slowly over thousands of years (1). (b) Draining lets air into the soil (1); decomposers respire aerobically and the stored carbon is released as carbon dioxide (1).

Final answer

(a) Waterlogged, anaerobic, acidic; decomposers inhibited; partly decomposed plant matter accumulates slowly. (b) Air enters; decomposers respire; carbon released as \ce{CO2}.

Question B3

[5 marks]
Thawing permafrost is described as a positive feedback in global warming. (a) Outline the stages by which warming of Arctic soils leads to further warming. [3] (b) Explain why more plant growth in response to extra carbon dioxide is a negative feedback. [1] (c) Identify one other positive feedback in global warming. [1]
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(a) Warming thaws the permafrost (1); decomposers break down the organic matter that was frozen (1); methane and carbon dioxide are released, strengthening the greenhouse effect and warming further (1). (b) The extra growth removes carbon dioxide, which opposes the warming (1). (c) Loss of ice and snow, so less sunlight is reflected; or warmer oceans releasing carbon dioxide; or drought and fire (1).

Final answer

(a) Soil thaws; decomposers break down stored organic matter; \ce{CH4}/\ce{CO2} released; more heat trapped. (b) It removes \ce{CO2}, reducing warming. (c) Ice and snow loss lowers reflection.

Question B4

[5 marks]
Satellite images show that the surface of part of the ocean has become warmer over 30 years. (a) Explain how a warmer surface layer affects marine primary production. [3] (b) Outline one effect of the change in primary production on a named consumer. [2]
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(a) Warm water is lighter, so a stable layer forms and mixes less with deeper water (1); less nutrient-rich water is brought to the surface (upwelling) (1); phytoplankton growth and primary production fall (1). (b) Any named consumer, for example a seabird (1) with less food, so lower breeding success or condition (1).

Final answer

(a) Stable warm layer; less upwelling of nutrients; less phytoplankton growth. (b) Fewer prey for fish or seabirds, so fewer breed.

Question B5

[6 marks]
Human activity has changed the global climate. (a) Explain the causes and the consequences of climate change. [6]
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(a) Any six linked points: burning fossil fuels releases \ce{CO2} (1); deforestation removes uptake and livestock and rice release \ce{CH4} (1); these gases absorb long-wave radiation and retain heat, strengthening the greenhouse effect (1); ice and snow melt, so less sunlight is reflected (1); oceans warm and absorb \ce{CO2}, so coral reefs bleach and calcify less (1); species shift towards the poles and uphill (1); drought and fire release more carbon (1); permafrost thaws and releases methane (1).

Final answer

Causes with gases and activities; mechanism; consequences: ice, ocean, range, fire, reefs.

Question B6

[6 marks]
The highest altitude at which five beetle species were found on a mountain was recorded in 1980 and in 2020.\begin{array}{lccccc}\hline \text{Species}&\text{P}&\text{Q}&\text{R}&\text{S}&\text{T}\\ \hline \text{1980 / m}&\text{1500}&\text{1800}&\text{2100}&\text{2300}&\text{1950}\\ \hline \text{2020 / m}&\text{1620}&\text{1890}&\text{2230}&\text{2330}&\text{2090}\\ \hline\end{array} (a) Calculate the mean upslope shift of the five species. [2] (b) Describe the pattern shown by the data. [1] (c) Suggest two effects of these shifts on the community of the mountain. [2] (d) Explain why a species whose range is already at the summit is at particular risk. [1]
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(a) Shifts are 120, 90, 130, 30, 140 m (1); mean =510/5=102 m (1). (b) All species have moved to a higher altitude, by between 30 and 140 m (1). (c) Any two: species from lower down compete with or prey on the residents; the area at higher altitude is smaller, so populations shrink; species with specialised needs decline; food-web relationships change (2). (d) It cannot move higher, so its habitat shrinks and it may go extinct (1).

Final answer

(a) 102 m. (b) All five moved upslope. (c) New competition or predation; smaller populations at higher altitude. (d) No higher ground, so range cannot shift.

Question B7

[7 marks]
In an aquarium experiment, a reef community was exposed to four levels of carbon dioxide in the air above the water. The mean calcification rate (\pm one standard deviation) is shown for each level, with five replicate tanks per level.\begin{array}{lcccc}\hline \text{}\ce{CO2}\text{ / }\mu\text{atm}&\text{280}&\text{400}&\text{600}&\text{800}\\ \hline \text{Calcification / mmol m}^{-2}\text{ d}^{-1}&\text{12.5 }\pm\text{ 0.6}&\text{10.0 }\pm\text{ 0.5}&\text{7.8 }\pm\text{ 0.6}&\text{6.5 }\pm\text{ 0.7}\\ \hline\end{array} (a) State the relationship between carbon dioxide level and calcification. [1] (b) Calculate the percentage decrease in calcification between 280 and 800 \muatm. [2] (c) State which treatment is the best control and give one variable kept constant. [1] (d) Using the standard deviations, state whether the decrease from 400 to 800 \muatm is likely to be real. [1] (e) Explain why higher carbon dioxide lowers calcification. [2]
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(a) As carbon dioxide rises, calcification falls (1). (b) Change =6.5-12.5=-6.0 (1); 6.0/12.5\times100=48\% decrease (1). (c) The 400 \muatm tank, the present-day level; any one of temperature, light, salinity, species present (1). (d) The ranges 9.5 to 10.5 and 5.8 to 7.2 do not overlap, so the difference is likely to be real (1). (e) Carbon dioxide dissolves in seawater and lowers its pH, so there are fewer carbonate ions (1); corals need carbonate to build calcium carbonate skeletons, so calcification slows (1).

Final answer

(a) Negative correlation. (b) 48 %. (c) 400 \muatm (present day); temperature, light, salinity. (d) Yes: ranges do not overlap. (e) \ce{CO2} dissolves, pH falls, fewer carbonate ions.

Question B8

[5 marks]
The growth rate of two species of marine copepod was measured at four temperatures.\begin{array}{lcccc}\hline \text{Temperature / }^\circ\text{C}&\text{10}&\text{15}&\text{20}&\text{25}\\ \hline \text{Species X / mm d}^{-1}&\text{0.20}&\text{0.31}&\text{0.45}&\text{0.30}\\ \hline \text{Species Y / mm d}^{-1}&\text{0.25}&\text{0.35}&\text{0.36}&\text{0.34}\\ \hline\end{array} (a) State the relationship between temperature and growth in species X from 10 to 20\,{}^\circC. [1] (b) State the temperature at which species X grows fastest. [1] (c) Evaluate the hypothesis that warming from 10 to 25\,{}^\circC increases the growth of both species. [2] (d) Predict the effect on species X of surface water warming from 20 to 25\,{}^\circC. [1]
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(a) Growth increases as temperature rises (positive correlation) (1). (b) 20\,{}^\circC (1). (c) Y grows faster at 25 than at 10 (0.34 against 0.25), but X does not keep rising: it peaks at 20 and falls to 0.30 (1); the hypothesis is supported for Y at the end points only and is not supported for X above 20\,{}^\circC, so overall it is not supported (1). (d) Growth rate of X falls (from 0.45 to 0.30 mm d^{-1}) (1).

Final answer

(a) Positive correlation. (b) 20\,{}^\circC. (c) Supported for Y (0.25 to 0.34) but not X (0.20 to 0.30 and peaks at 20). (d) Growth falls.

Question B9

[7 marks]
Researchers counted the chicks fledged by an emperor penguin colony over five winters and recorded the winter extent of sea ice in the region.\begin{array}{lccccc}\hline \text{Sea ice / million km}^2&\text{18.5}&\text{17.2}&\text{16.0}&\text{14.8}&\text{13.1}\\ \hline \text{Chicks fledged per 100 pairs}&\text{72}&\text{66}&\text{59}&\text{47}&\text{38}\\ \hline\end{array} (a) Describe the relationship between sea ice extent and chick production. [2] (b) Calculate the percentage decrease in chicks fledged per 100 pairs between the first and last winter. [2] (c) Suggest two reasons why less ice reduces breeding success. [2] (d) State why these data alone do not prove that ice loss caused the decline. [1]
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(a) As ice extent falls from 18.5 to 13.1 million km^2 (1), chicks fledged fall from 72 to 38 per 100 pairs: a positive correlation (1). (b) 38-72=-34 (1); 34/72\times100=47\% decrease (1). (c) Any two: breeding sites on landfast ice are lost or break out early; the ice-algae base of the food chain is reduced, so less food; chicks fall into the water or are not fledged by the time ice breaks (2). (d) A correlation does not show cause, and other factors such as food supply or predators may also have changed over the five winters (1).

Final answer

(a) Positive correlation: less ice, fewer chicks. (b) 47 %. (c) Breeding ground lost; less ice-associated food. (d) Correlation; other variables.

Question B10

HL[5 marks]
In a woodland the date of peak caterpillar abundance and the date at which blue tit chicks hatch were recorded in years with different April temperatures. Days are counted from 1 January. The tits time laying by daylength.\begin{array}{lcccc}\hline \text{Mean April temperature / }^\circ\text{C}&\text{6.0}&\text{7.0}&\text{8.0}&\text{9.0}\\ \hline \text{Caterpillar peak / day}&\text{150}&\text{144}&\text{138}&\text{131}\\ \hline \text{Chick hatching / day}&\text{146}&\text{146}&\text{146}&\text{146}\\ \hline\end{array} (a) State the relationship between April temperature and the date of the caterpillar peak. [1] (b) Calculate the number of days between the caterpillar peak and chick hatching at 6.0 and at 9.0\,{}^\circC, stating which comes first. [2] (c) Explain the consequence for the chicks and how selection might respond. [2]
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(a) The warmer the April, the earlier the caterpillar peak (negative correlation with date) (1). (b) At 6.0: 150-146=4 days, the peak comes after hatching (1); at 9.0: 146-131=15 days, the peak comes before hatching (1). (c) The chicks hatch after the peak of food, so there is less food and fewer survive (1); birds that lay earlier match the new peak, leave more offspring, and the early-laying allele becomes more frequent (1).

Final answer

(a) Higher temperature, earlier peak. (b) 4 days after hatching; 15 days before hatching. (c) Mismatch; chicks starve; early layers favoured.

Advanced practice

Question C1

[8 marks]
A boreal forest region was monitored for four decades.\begin{array}{lcccc}\hline \text{Decade}&\text{1980s}&\text{1990s}&\text{2000s}&\text{2010s}\\ \hline \text{Winter snowfall index}&\text{100}&\text{95}&\text{88}&\text{80}\\ \hline \text{Summer drought days}&\text{12}&\text{15}&\text{22}&\text{31}\\ \hline \text{Area burned / \% per decade}&\text{0.8}&\text{1.1}&\text{1.9}&\text{3.2}\\ \hline \text{Net carbon balance / g C m}^{-2}\text{ yr}^{-1}&\text{+45}&\text{+30}&\text{+8}&-25\\ \hline\end{array} (a) Describe the change in the net carbon balance and calculate its total change. [2] (b) Explain how reduced winter snowfall can lower carbon uptake. [2] (c) Explain how the burned area data help to account for the net balance, using the idea of legacy carbon. [2] (d) Explain why the switch is described as a tipping point and a positive feedback. [2]
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(a) The balance falls steadily from a net gain of 45 to a net loss of 25 (1); change =-25-45=-70 g C m^{-2} yr^{-1} (1). (b) Less snow means less meltwater stored for summer, so drought stress increases (1); trees close stomata or die back, so photosynthesis and primary production fall (1). (c) Burned area rose from 0.8 to 3.2 % (four times) (1); severe fires burn into the soil organic layer and release legacy carbon stored for decades, so release exceeds the reduced uptake (1). (d) Beyond the point where release exceeds uptake the forest adds \ce{CO2} to the air (1); that warms the climate further, causing more drought and fire: a positive feedback that is hard to reverse (1).

Final answer

(a) Falls from +45 to -25: change -70. (b) Less snow, drought, lower production. (c) Fire burns soil legacy carbon; burned area \times4. (d) Self-reinforcing: more \ce{CO2} warms more.

Question C2

HL[7 marks]
A bark beetle needs 700 degree-days above a threshold of 7\,{}^\circC to complete one generation: each day with a mean temperature T gives T-7 degree-days. The beetle can breed for 140 days each year. Assume the mean temperature during the season is 13.0\,{}^\circC today and 17.5\,{}^\circC in 2050. (a) Calculate the number of whole generations per year today and in 2050. [3] (b) Each generation multiplies the number of beetles 20-fold. Compare the increase in numbers in one year today and in 2050. [2] (c) Suggest two consequences for the forest of this change. [2]
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(a) Today: 700/(13.0-7)=116.7 days per generation (1); 140/116.7=1.2, so 1 whole generation (1). 2050: 700/(17.5-7)=66.7 days; 140/66.7=2.1, so 2 generations (1). (b) Today \times20; in 2050 20^2=\times400 (1); 20 times as many beetles at the end of the year (1). (c) More spruce are attacked and killed (1); dead trees stop sequestering carbon and decompose or burn, releasing carbon, which adds to warming (1).

Final answer

(a) Today 1; 2050 2. (b) \times20 against \times400: 20 times more. (c) More trees killed; less carbon stored.

Question C3

HL[6 marks]
Tawny owls have a grey and a brown colour variant. Winter survival was measured in winters with long snow cover (more than 100 days) and winters with short snow cover (fewer than 40 days).\begin{array}{lcc}\hline \text{Variant}&\text{Long snow cover}&\text{Short snow cover}\\ \hline \text{Grey}&\text{0.71}&\text{0.60}\\ \hline \text{Brown}&\text{0.58}&\text{0.69}\\ \hline\end{array} (a) Calculate how much higher the survival of grey owls is than that of brown owls in long snow-cover winters. [1] (b) Explain how the data show that selection favours a different variant in each type of winter. [3] (c) Predict and justify the change in the allele frequencies if snow cover keeps falling for many years. [2]
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(a) 0.71-0.58=0.13 (1). (b) In long snow winters grey owls survive better (0.71 against 0.58) and in short snow winters brown survive better (0.69 against 0.60) (1); the variant that matches the background is detected less by predators or prey (camouflage) (1); survival differences mean the favoured variant leaves more offspring, so each winter type selects for a different variant (1). (c) Short-snow winters become more common, so brown survives and breeds more (1); the frequency of the brown allele rises across generations: climate change drives evolution (1).

Final answer

(a) 0.13. (b) Grey survives better in snow; brown in short snow; camouflage. (c) Brown allele frequency rises.

Question C4

[8 marks]
The graph shows monthly atmospheric carbon dioxide at one monitoring station from 2010 to 2020. The annual mean was 390 ppm in 2010 and 414 ppm in 2020. [Graph: A line graph of monthly carbon dioxide (ppm, 380 to 420) from 2010 to 2020: a steady upward trend of about 2.4 ppm per year with a regular seasonal wave of about 3 ppm either side of the trend.] (a) Describe two features of the record. [2] (b) Calculate the percentage increase in the annual mean from 2010 to 2020. [2] (c) Explain the yearly fluctuation seen on the graph. [2] (d) Evaluate whether this graph alone shows that rising carbon dioxide causes warming. [2]
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(a) A long-term rise (1) with a regular yearly cycle of about 6 ppm (1). (b) 414-390=24 (1); 24/390\times100=6.2\% (1). (c) In the summer growing season of the northern hemisphere, land plants take up more carbon dioxide in photosynthesis than they release, so concentration falls (1); in winter respiration and decay exceed uptake, so concentration rises (1). (d) The graph contains no temperature data, so it cannot show a link to warming (1); even with temperature data, a correlation alone does not prove cause: the mechanism (absorption of long-wave radiation) and other evidence are needed (1).

Final answer

(a) Rising trend with yearly cycle. (b) 6.2 %. (c) Northern summer photosynthesis removes \ce{CO2}; winter respiration. (d) Shows no temperature data; correlation not cause.

Question C5

[8 marks]
Coral fragments were kept for six weeks in four treatments. The algae density and calcification rate are means \pm one standard deviation (n=10 fragments each).\begin{array}{lcccc}\hline \text{Treatment}&\text{26 }^\circ\text{C, pH 8.1}&\text{29 }^\circ\text{C, pH 8.1}&\text{26 }^\circ\text{C, pH 7.8}&\text{29 }^\circ\text{C, pH 7.8}\\ \hline \text{Algae / }10^6\text{ cells cm}^{-2}&\text{2.0 }\pm\text{ 0.2}&\text{1.1 }\pm\text{ 0.2}&\text{1.9 }\pm\text{ 0.2}&\text{0.7 }\pm\text{ 0.2}\\ \hline \text{Calcification / mg cm}^{-2}\text{ d}^{-1}&\text{1.00 }\pm\text{ 0.08}&\text{0.85 }\pm\text{ 0.09}&\text{0.62 }\pm\text{ 0.07}&\text{0.40 }\pm\text{ 0.06}\\ \hline\end{array} (a) Identify which single factor changed the algae density, using the data. [1] (b) Calculate the percentage change in calcification between the first and last treatment. [2] (c) Deduce the separate effects of warming and of acidity, and explain each with a mechanism. [3] (d) Predict the effect of both changes on a reef community. [2]
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(a) Warming: 1.1 against 2.0 with no overlap of error ranges, while at 26 ^\circC pH made little difference (1.9 against 2.0) (1). (b) 0.40-1.00=-0.60 (1); 0.60/1.00\times100=60\% decrease (1). (c) Warming lowers algae density (bleaching), so less food is supplied and calcification falls a little (0.85) (1); acidity lowers calcification (0.62) without changing algae, so the effect is on skeleton building through a lower carbonate ion concentration (1); together the effects add up, giving the lowest values (1). (d) Coral cover declines and the skeleton structure erodes (1); habitat is lost, so the species that depend on it decline (1).

Final answer

(a) Temperature. (b) -60\%. (c) Warming: algae lost, bleaching; acidity: carbonate lower, calcification down. (d) Less coral cover and habitat; biodiversity falls.

Connected questions

Question X1

Connected questions[8 marks]
D4.3 + C4.2. In a model forest plot the gross primary production (GPP) is 24 t C ha^{-1} yr^{-1} in a normal year, and plant respiration is 11. Decomposers release 10.5 and fires release 1.0. In a drought year GPP is 19, plant respiration is 10, decomposers release 10.5 and fires release 3.0. The net primary production (NPP) is GPP minus plant respiration. (a) Calculate NPP in each year and the net balance of the plot (NPP minus decomposer and fire release). [3] (b) Explain how a drought year can turn the plot into a carbon source and why this may add to warming. [3] (c) Explain how rewetting a drained peatland differs from this plot in its effect on decomposers. [2]
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(a) Normal NPP =24-11=13; drought NPP =19-10=9 (1). Normal balance =13-(10.5+1.0)=+1.5 (1); drought balance =9-(10.5+3.0)=-4.5 t C ha^{-1} yr^{-1} (1). (b) Drought lowers photosynthesis, so NPP falls (1); fire release rises while decomposers keep releasing carbon, so release exceeds uptake and the plot is a source (1); the extra \ce{CO2} adds to warming, which makes drought and fire more likely: positive feedback (1). (c) In a rewetted peatland the water excludes oxygen, so decomposers are inhibited and carbon accumulates (1) whereas in the forest plot aerobic decomposers continue to release carbon each year (1).

Final answer

(a) NPP 13 and 9; balance +1.5 and -4.5. (b) Less production, more fire, decomposers continue: feedback. (c) Waterlogging stops decomposers, storing carbon.

Question X2

Connected questions[6 marks]
D4.3 + D4.2. A coral reef has 60% living coral cover. Each bleaching event removes 35 percentage points of cover, and recovery adds 2.5 percentage points per year. Mass bleaching has returned every 6 years. (a) Calculate the time the reef would need to recover fully from one event, starting from the cover after bleaching. [2] (b) Using the figures, explain why the reef cannot recover when bleaching returns every 6 years. [2] (c) Explain how this is an example of a loss of stability and of a tipping point. [2]
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(a) Cover after bleaching =60-35=25\% (1); time =35/2.5=14 years (1). (b) In 6 years the reef gains 6\times2.5=15 points (1), but each event removes 35, so cover falls by 20 points each cycle and cannot return to 60% (1). (c) The community cannot return to its original state after disturbance: it has lost resilience (1); beyond a threshold the reef shifts to algae-dominated seabed, which is hard to reverse even if warming stops (1).

Final answer

(a) 14 years. (b) Gains 15 per cycle, loses 35: net fall. (c) Cover below recovery level; algae dominate.

Question X3

Connected questions[6 marks]
D4.3 + C4.1. An alpine plant was sampled with random 1 m^2 quadrats (10 per altitude) in 1990 and 2020. The values are mean density.\begin{array}{lccc}\hline \text{Altitude / m}&\text{1900}&\text{2100}&\text{2300}\\ \hline \text{Density 1990 / m}^{-2}&\text{12.0}&\text{8.0}&\text{1.0}\\ \hline \text{Density 2020 / m}^{-2}&\text{4.0}&\text{9.5}&\text{6.0}\\ \hline\end{array} (a) Describe the change in the distribution of the plant. [2] (b) Suggest how the colonisation of the 2300 m zone might affect other species there, using the term competition. [2] (c) Outline how the survey should be carried out to make the comparison valid. [2]
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(a) Density has fallen at 1900 m (12.0 to 4.0) (1) and risen at 2100 and 2300 m (to 9.5 and 6.0), which is an upslope shift (1). (b) The newcomers compete with residents for light, water, nutrients or space (1); species with a lower competitive ability decline, so the community changes (1). (c) Quadrats placed randomly with the same number and area at each altitude and at the same time of year (1); the same method in 1990 and 2020 so the difference is due to climate and not to the method (1).

Final answer

(a) Density falls at 1900 and rises at 2100 and 2300: upslope shift. (b) Competes for light, water, space; some native species decline. (c) Same quadrats, random placement, same season.

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Photon Biology: Study Guide for the IB Diploma (SL & HL)

Climate change from the core ideas to full exam questions, with question types, worked examples and graded practice.

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