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IB Biology C4.2: Transfers of energy and matter worked solutions

Worked solutions to every practice question in C4.2: Transfers of energy and matter of Photon Biology: Study Guide for the IB Diploma (SL & HL). Try each question, then compare your working with the full solution.

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Basic practice

Question A1

[1 mark]
Which statement describes an open ecosystem that stays stable over many years? (A) Energy and matter are both recycled. (B) Energy flows through and matter is recycled. (C) Matter flows through and energy is recycled. (D) Neither energy nor matter enters or leaves.
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B. Energy enters, flows through and leaves as heat, while matter such as carbon and nitrogen is recycled by decomposers. A and C let energy be recycled or matter be lost, and D describes a closed system with no energy supply.

Final answer

B

Question A2

[1 mark]
Which row gives the external energy source of each type of autotroph? (A) Light for both (B) Photoautotroph: light; chemoautotroph: oxidation of inorganic substances (C) Photoautotroph: oxidation of inorganic substances; chemoautotroph: light (D) Oxidation of inorganic substances for both
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B. Photoautotrophs use light. Chemoautotrophs use energy released by oxidising inorganic substances such as sulfur compounds. A gives light to both, C swaps the pair and D gives oxidation to both.

Final answer

B

Question A3

[1 mark]
In a woodland, the arrows are: leaves \to caterpillar; leaves \to vole; caterpillar \to blue tit; caterpillar \to shrew; blue tit \to sparrowhawk; vole \to sparrowhawk. Which statement is correct? (A) The sparrowhawk is both a secondary and a tertiary consumer. (B) The shrew is a primary consumer. (C) The vole is a secondary consumer. (D) The blue tit is a producer.
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A. The sparrowhawk eats a vole, a primary consumer, so it is a secondary consumer there, and a blue tit, a secondary consumer, so it is a tertiary consumer there. The shrew eats a caterpillar, so it is a secondary consumer; the vole is a primary consumer and the blue tit is a secondary consumer, not a producer.

Final answer

A

Question A4

[1 mark]
Heterotrophs build new tissue from the carbon compounds they eat. Which term names the carbon compounds they add to their biomass? (A) Primary production (B) Gross respiration (C) Secondary production (D) Light absorption
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C. That is secondary production. Primary production is the same gain made by autotrophs, and neither respiration nor the light absorbed by leaves is production.

Final answer

C

Question A5

[1 mark]
A pyramid of energy for a field shows 5000 kJ m^{-2} yr^{-1} in producers, 600 in primary consumers and 70 in secondary consumers. What percentage of the producers' energy passes to the primary consumers? (A) 88% (B) 12% (C) 11.7% (D) 1.4%
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B. 600\div5000\times100=12\%. A is the share that does not pass on, C is 70\div600 and D is 70\div5000.

Final answer

B

Question A6

[1 mark]
Which is the main reason why food chains rarely have more than five trophic levels? (A) Top carnivores cannot catch enough prey. (B) Biomass increases at each level. (C) Little energy remains after repeated losses as heat. (D) Decomposers cannot feed on top carnivores.
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C. At each transfer much of the energy is lost as heat from respiration and left in uneaten or indigestible parts, so too little remains to support another level. Energy is not recycled and biomass does not increase up a chain.

Final answer

C

Question A7

[1 mark]
In a carbon-cycle diagram an arrow runs from dead leaves in the soil to carbon dioxide in the air. Which process does it show? (A) Photosynthesis (B) Combustion (C) Fossilization (D) Respiration by decomposers
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D. Decomposers respire the carbon compounds in dead leaves and release carbon dioxide. Photosynthesis takes carbon dioxide in, combustion needs burning and fossilization stores carbon.

Final answer

D

Question A8

[1 mark]
Which change would turn a forest from a net carbon sink into a net carbon source? (A) Planting seedlings (B) Large-scale burning of the trees (C) Increased photosynthesis (D) Slow growth of young trees
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B. Burning or clearing releases stored carbon and removes the producers that take it in. Planting seedlings and increased photosynthesis increase the sink, and slow growth leaves it small but still positive.

Final answer

B

Question A9

[1 mark]
Atmospheric carbon dioxide at Mauna Loa falls from May to October each year. What is the best explanation? (A) Less fuel is burned in summer. (B) Northern plants take up more carbon dioxide than organisms release. (C) The oceans release carbon dioxide. (D) Decomposers are more active.
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B. In the northern spring and summer photosynthesis in the large northern land vegetation exceeds respiration, so there is a net uptake of carbon dioxide. Combustion does not fall in summer, and the other options would raise the level.

Final answer

B

Question A10

[1 mark]
Which statement about oxygen and carbon dioxide in the biosphere is correct? (A) Each process supplies the gas the other needs. (B) Respiration releases oxygen for photosynthesis. (C) Only plants respire. (D) Photosynthesis releases carbon dioxide.
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A. Aerobic respiration depends on the oxygen released by photosynthesis, and photosynthesis depends on the carbon dioxide released by respiration. B reverses the gases, and C and D describe only one process.

Final answer

A

Tutorial practice

Question B1

[7 marks]
On a rocky coast, sea urchins and snails feed on kelp. Crabs feed on snails and on sea urchins. Sea otters feed on sea urchins and on crabs. (a) Write the food web as pairs of the form food \to feeder. [3] (b) State the trophic level or levels at which the sea otter feeds. [2] (c) Predict one effect on the kelp of removing all sea otters. [2]
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(a) Each arrow runs from the food to the feeder: kelp to urchin, kelp to snail, urchin to crab, snail to crab, urchin to otter, crab to otter. All six correct (3); four or five correct (2); two or three correct (1). (b) The otter eats urchins, which are primary consumers, so it is a secondary consumer (1). It also eats crabs, which are secondary consumers, so it is a tertiary consumer (1). (c) Without otters the urchins lose a predator and increase in number (1). More urchins graze more kelp, so the kelp decreases (1). Credit a reasoned answer that notes the crabs, which also eat urchins, may increase and partly offset this.

Final answer

(a) kelp\tourchin; kelp\tosnail; urchin\tocrab; snail\tocrab; urchin\tootter; crab\tootter. (b) Secondary consumer (eating urchins) and tertiary consumer (eating crabs). (c) Urchins lose a predator and increase, so they eat more kelp and the kelp falls.

Question B2

[4 marks]
A farmed fish takes in 2400 kJ of food energy per day. Faeces carry away 600 kJ and respiration releases 1560 kJ. (a) Calculate the energy that goes into growth. [1] (b) Calculate the percentage of the ingested energy that becomes biomass. [1] (c) Calculate the growth as a percentage of the energy absorbed. [1] (d) Suggest why a more active fish converts a smaller percentage. [1]
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(a) 2400-600-1560=240\,\mathrm{kJ} goes into growth (1). (b) 240\div2400\times100=10\% of the ingested energy (1). (c) The energy absorbed is 2400-600=1800\,\mathrm{kJ}, so 240\div1800\times100=13.3\% (1). (d) A fish that swims more respires more, releasing more energy as heat, so a smaller share of the food becomes biomass (1).

Final answer

(a) 240 kJ. (b) 10%. (c) 13.3%. (d) More energy is released in respiration for movement, so less is left for growth.

Question B3

[5 marks]
Energy flow in a lake was measured over one year. A pyramid of energy is to be drawn. Energy flow in kJ per square metre per year: producers 4800; primary consumers 520; secondary consumers 61; tertiary consumers 5. (a) Construct the pyramid, stating the scale you use. [3] (b) Calculate the percentage of energy passed from primary to secondary consumers. [1] (c) Suggest why the tertiary bar is almost invisible. [1]
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(a) A scale stated and used, for example 1\,\mathrm{cm}=500\,\mathrm{kJ\,m^{-2}\,yr^{-1}}, giving bars of 9.6 cm, 1.04 cm, 0.12 cm and 0.01 cm (1); bars of equal height, centred, producers at the base (1); each bar labelled with its trophic level and the units (1). (b) 61\div520\times100=11.7\% (1). (c) The tertiary step is 5\div61\times100=8.2\%, similar to the others, so the top bar is tiny because of the repeated losses below it, not because that step is unusually inefficient (1).

Final answer

(a) Scale 1 cm = 500 kJ m^{-2} yr^{-1}: bars 9.6 cm, 1.04 cm, 0.12 cm, 0.01 cm; equal heights, centred, labelled with levels and units. (b) 11.7%. (c) 8.2% is similar, so the small top bar is caused by the small amount of energy entering from below.

Question B4

[6 marks]
Describe how energy enters, flows through and leaves a grassland ecosystem.
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Any six of: sunlight is the energy source (1); producers absorb light and convert it to chemical energy in carbon compounds by photosynthesis (1); chemical energy passes to consumers by feeding (1); each trophic level uses energy in cell respiration (1); respiration releases energy for ATP and heat (1); energy is lost as heat, which leaves the ecosystem (1); dead organisms and waste pass chemical energy to decomposers (1); energy is not recycled, so a continuous supply of light is needed (1).

Final answer

Light is absorbed by grasses, which convert it to chemical energy in carbohydrates. Chemical energy passes along the food chain by feeding and to decomposers when organisms die. In respiration each organism releases energy, which ends as heat leaving the ecosystem. It is not recycled.

Question B5

[4 marks]
Explain why the biomass of tertiary consumers in an ecosystem is much smaller than that of primary consumers, although a gram of tissue holds about the same energy at every level.
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Energy is lost at each trophic level as heat from cell respiration (1). It is also lost in indigestible and uneaten parts (1). Less energy is therefore available to each higher level, so fewer or smaller organisms can be supported (1). Because a gram of tissue holds about the same energy at every level, less total energy means less biomass (1).

Final answer

Energy is lost at every transfer, mainly as heat from respiration, and in faeces and uneaten parts. Less energy reaches the higher level, so it supports fewer or smaller organisms. Energy per gram is similar, so lower total energy means less mass.

Question B6

[6 marks]
Outline the carbon cycle in a forest. Include two processes that return carbon dioxide to the air and one that stores carbon for a long time.
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Photosynthesis moves carbon dioxide from the air into carbon compounds in the trees (1). Feeding passes carbon compounds to consumers (1). Dead organisms and waste pass carbon to decomposers (1). Respiration by plants, animals and decomposers returns carbon dioxide (1); combustion, for example a forest fire, also returns it (1). Long-term storage: peat formed in waterlogged, anaerobic, acid soil, or fossilization to fossil fuels (1).

Final answer

Trees absorb carbon dioxide in photosynthesis and build carbon compounds. Consumers eat them, and plants, animals and decomposers return carbon dioxide by respiration. Burning also returns it. Waterlogged conditions can form peat and long burial forms fossil fuels, which store carbon.

Question B7

[5 marks]
Two plots of young woodland were surveyed. Plot X is 0.80 ha and plot Y is 1.50 ha. The carbon in living biomass was measured three years apart. Carbon in living biomass in tonnes: plot X (0.80 ha) 18.0 at the start and 27.6 after 3 years; plot Y (1.50 ha) 30.0 at the start and 42.0 after 3 years. (a) Calculate the primary production of plot X in g C m^{-2} yr^{-1}. [3] (b) Calculate the primary production of plot Y. [1] (c) State which plot is more productive and why the larger total gain of the other plot is misleading. [1]
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(a) Gain =27.6-18.0=9.6 tonnes of carbon (1); 9.6\times10^6\,\mathrm{g}\div8000\,\mathrm{m^2}=1200\,\mathrm{g\,m^{-2}} (1); 1200\div3=400\,\mathrm{g\,C\,m^{-2}\,yr^{-1}} (1). (b) 12\times10^6\div15\,000\div3=267\,\mathrm{g\,C\,m^{-2}\,yr^{-1}} (1). (c) Plot X has the higher production, because production is a rate per square metre per year; Y gained more in total only because it is larger (1).

Final answer

(a) 400\,\mathrm{g\,C\,m^{-2}\,yr^{-1}}. (b) 267\,\mathrm{g\,C\,m^{-2}\,yr^{-1}}. (c) Plot X: Y gains more in total because it is larger, but the production per unit area is lower.

Question B8

[5 marks]
A peatland takes in 520\ \mathrm{g\,C\,m^{-2}\,yr^{-1}} by photosynthesis. Each year it releases 240 by plant respiration, 190 by decomposition, 12 as methane and 18 in small fires, all in the same units. (a) Calculate the net carbon exchange. [2] (b) State whether the peatland is a sink or a source. [1] (c) A drought raises decomposition to 330 and nothing else changes. Calculate the new net exchange, state the result and give the cause. [2]
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(a) Release =240+190+12+18=460 (1); net =520-460=+60\,\mathrm{g\,C\,m^{-2}\,yr^{-1}} (1). (b) Positive, so the peatland is a net carbon sink (1). (c) Decomposition rises to 330, so release is 240+330+12+18=600 and the net is 520-600=-80, a net source (1). The drought lowers the water level, air enters the peat and decomposers respire the stored carbon (1).

Final answer

(a) +60. (b) Sink. (c) -80, a source: drought raises decomposition because air enters the peat.

Question B9

[5 marks]
The table shows nutrient stores in two ecosystems. Nutrient stores in kg per hectare, rainforest then boreal forest: biomass 430 and 120; litter 5 and 60; soil 25 and 220. (a) State the largest store in each ecosystem. [1] (b) Suggest why the litter store of the rainforest is so small. [2] (c) Predict the effect on soil fertility of clearing and removing the rainforest trees. [2]
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(a) Rainforest: biomass (430); boreal forest: soil (220) (1). (b) Litter is decomposed quickly in the warm, moist conditions (1) and the released nutrients are taken up quickly by plants, so little accumulates in the litter (1). (c) Clearing and removing the trees takes away most of the nutrients, which are held in the biomass (1); the soil store is small, so soil fertility falls quickly (1).

Final answer

(a) Biomass in the rainforest; soil in the boreal forest. (b) Warm, wet conditions let decomposers break litter down quickly, and roots take up nutrients fast. (c) Clearing removes the main store, and the small soil store cannot support crops for long.

Advanced practice

Question C1

[6 marks]
Pondweed in a sealed, stirred jar of water was kept for one hour in the dark and for one hour in bright light. The change in dissolved oxygen was -1.5\ \mathrm{mg\,dm^{-3}\,h^{-1}} in the dark and +3.6\ \mathrm{mg\,dm^{-3}\,h^{-1}} in bright light. (a) The dark jar measures respiration alone. Calculate the rate of photosynthesis in \mathrm{mg\,dm^{-3}\,h^{-1}} as oxygen released. [2] (b) Explain the change in oxygen and in carbon dioxide in the dark jar. [2] (c) Explain how, in an ecosystem, each process depends on the other. [2]
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(a) The dark jar measures respiration alone, because there is no photosynthesis without light, so the light jar's net gain understates photosynthesis: net change in light = photosynthesis - respiration, so photosynthesis =3.6+1.5=5.1\,\mathrm{mg\,dm^{-3}\,h^{-1}} (2). (b) Aerobic respiration oxidises carbon compounds using oxygen, so oxygen falls (1), and it releases carbon dioxide, so that rises (1). (c) Photosynthesis releases oxygen, which aerobic respiration uses (1); respiration releases carbon dioxide, which photosynthesis uses (1).

Final answer

(a) 5.1\ \mathrm{mg\,dm^{-3}\,h^{-1}}. (b) Respiration uses oxygen and releases carbon dioxide. (c) Respiration releases the carbon dioxide that photosynthesis needs; photosynthesis releases the oxygen that respiration needs.

Question C2

[6 marks]
A cave pool receives no light. Bacteria on the rock oxidise hydrogen sulfide from the water and use the energy to make carbohydrates from carbon dioxide. Cave shrimps eat the bacteria. A blind fish eats the shrimps. (a) Classify the bacteria using two terms. [2] (b) State the source of energy for the bacteria. [1] (c) Describe how energy flows through the pool, naming the trophic level of the fish, and how it leaves. [3]
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(a) The bacteria make carbon compounds from carbon dioxide, so they are autotrophs (1), and they use oxidation of an inorganic substance as the energy source, so they are chemoautotrophs (1). (b) Oxidation of hydrogen sulfide (1). (c) Energy enters the community as chemical energy in the carbon compounds made by the bacteria (1); it passes to the shrimps, which are primary consumers, and then to the fish, a secondary consumer, by feeding (1); at each level respiration releases heat, which leaves the pool, and none of it is recycled (1).

Final answer

(a) Chemoautotroph and autotroph (producer). (b) Oxidation of hydrogen sulfide. (c) Chemical energy in carbon compounds passes by feeding; each level loses heat by respiration; it is not recycled.

Question C3

[6 marks]
A scientist recorded atmospheric carbon dioxide at a northern station. The table gives the yearly mean and the highest and lowest monthly values. Carbon dioxide in ppm for 2018, 2019, 2020 and 2021: yearly mean 408.0, 410.5, 413.0, 415.5; highest month 411.4, 413.9, 416.4, 418.9; lowest month 404.6, 407.1, 409.6, 412.1. (a) Describe the long-term trend, quoting values, and calculate the difference between the highest and lowest monthly values in 2018. [2] (b) Explain the yearly rise and fall, stating whether northern vegetation is a net sink or source between May and October. [2] (c) Explain the long-term trend. [2]
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(a) The yearly mean rises each year from 408.0 to 415.5 ppm (1), an increase of 7.5 ppm in three years or 2.5 ppm a year (1). (b) Swing in 2018: 411.4-404.6=6.8\,\mathrm{ppm} (1). The high is in late spring and the low in early autumn; in spring and summer northern plants take up more carbon dioxide in photosynthesis than organisms release in respiration, so the level falls, which makes the northern vegetation a net carbon sink between May and October, and in autumn and winter respiration exceeds photosynthesis (1). (c) Combustion of coal, oil, gas, peat and wood releases carbon dioxide (1) faster than photosynthesis and the oceans remove it (1).

Final answer

(a) Rises from 408.0 to 415.5 ppm, 7.5 ppm in 3 years, 2.5 ppm a year; yearly swing 6.8 ppm. (b) Northern plants take up more carbon dioxide than organisms release in spring and summer, and less in autumn and winter, so the northern vegetation is a net sink from May to October. (c) Combustion of fossil fuels, biomass and peat.

Question C4

[7 marks]
Energy flow into biomass in a lake was measured over one year. Energy in new biomass in kJ per square metre per year: phytoplankton 6000; zooplankton 840; small fish 100; pike 9. (a) Distinguish between primary production and secondary production, and state which value in the table is primary production. [2] (b) Calculate the percentage of energy passed from zooplankton to small fish and from small fish to pike. [2] (c) A student says the pike receive little energy because the last step is the least efficient. Evaluate this claim using the data. [3]
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(a) Primary production is the carbon compounds autotrophs add to their stored biomass (1); secondary production is the carbon compounds heterotrophs add to theirs (1). Phytoplankton is the primary production, and the other three are secondary production. (b) Zooplankton to small fish =100\div840\times100=11.9\% (1); small fish to pike =9\div100\times100=9\% (1). (c) The first step is 840\div6000=14.0\%, so the percentage hardly changes between steps (1); the pike get little energy because losses add up through the earlier levels, not because that step is unusually inefficient (1); the claim is not supported (1).

Final answer

(a) Primary production is the carbon autotrophs (phytoplankton) add to their biomass; secondary production is the carbon heterotrophs (the other three) add to theirs. (b) 100\div840=11.9\%; 9\div100=9\%. (c) The last step, 9%, is close to the others (14.0% and 11.9%), so the pike are not unusually inefficient; they get little because so little energy reaches them.

Connected questions

Question X1

Connected questions[6 marks]
C4.2 + C1.3 + D4.3. A plantation of fast-growing trees is planted on former pasture. (a) Explain why the plantation is a carbon sink while the trees are growing. [2] (b) State the raw materials of photosynthesis and the product that stores the energy. [1] (c) Explain how burning the harvested wood affects the enhanced greenhouse effect. [3]
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(a) Photosynthesis exceeds respiration in the growing trees (1), so carbon dioxide is taken up and carbon accumulates in the biomass, making the plantation a net sink (1). (b) Raw materials: carbon dioxide and water; the product that stores energy is a carbohydrate such as glucose (1). (c) Burning the wood is combustion, which releases the stored carbon as carbon dioxide (1); carbon dioxide absorbs infrared radiation and re-emits it, which warms the atmosphere, the enhanced greenhouse effect (1); the carbon released returns the plantation to being a source (1).

Final answer

(a) While the trees grow, photosynthesis exceeds respiration, so there is net uptake of carbon dioxide and carbon builds up in the wood. (b) Carbon dioxide and water; glucose or carbohydrate stores the energy. (c) Burning releases the stored carbon as carbon dioxide, a greenhouse gas that absorbs and re-emits infrared radiation, so it adds to warming.

Question X2

Connected questions[6 marks]
C4.2 + B4.2 + C4.1. Earthworms and fungi in a woodland soil feed on dead leaves. (a) Distinguish between earthworms and fungi as feeders on dead matter. [2] (b) Explain how these organisms keep elements available to plants. [2] (c) Predict the effect on the earthworm population of a drop in leaf fall, using the idea of carrying capacity. [2]
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(a) Earthworms are detritivores, which ingest dead organic matter and digest it inside the body (1). Fungi are saprotrophs, which secrete digestive enzymes onto the matter and absorb the products (1). (b) Decomposers break down dead matter to release the elements in it (1), which are taken up by plants and used again, so elements are recycled (1). (c) Less leaf litter means less food (1), so the carrying capacity for the earthworm population falls and the population declines (1).

Final answer

(a) Earthworms are detritivores: they ingest dead matter and digest it internally. Fungi are saprotrophs: they secrete enzymes and absorb the products. (b) They break down dead matter and release the elements in it for plants to take up again. (c) Fewer leaves means less food, so the carrying capacity of the earthworm population falls.

Question X3

Connected questions[6 marks]
C4.2 + C1.2 + D4.3. Soil microorganisms respire carbon compounds from dead plants. Their release of carbon dioxide rises as the soil warms from 5\,{}^{\circ}\mathrm{C} to 25\,{}^{\circ}\mathrm{C}. (a) Explain why the carbon dioxide release increases with temperature. [2] (b) Outline why this could cause positive feedback in climate change. [2] (c) Suggest why waterlogged peat releases much less carbon dioxide than well-drained soil. [2]
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(a) Respiration is catalysed by enzymes (1); a higher temperature gives more collisions and faster reaction rates, so more carbon dioxide is released (1). (b) A warmer climate raises the release of carbon dioxide from soil (1); the added carbon dioxide strengthens the greenhouse effect and warms the climate further, which is a positive feedback (1). (c) In waterlogged peat there is little oxygen (1), the soil is acid, and decomposers cannot fully decompose the plants, so carbon stays stored (1).

Final answer

(a) Respiration is controlled by enzymes, which work faster as the temperature rises, so more carbon dioxide is released. (b) Warming raises release, which adds carbon dioxide and warms more: positive feedback. (c) Waterlogged peat has little oxygen and is acidic, so decomposers cannot respire or work, and the carbon stays stored.

From the book

Photon Biology: Study Guide for the IB Diploma (SL & HL)

Transfers of energy and matter from the core ideas to full exam questions, with question types, worked examples and graded practice.

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