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IB Biology A4.2: Conservation of biodiversity worked solutions

Worked solutions to every practice question in A4.2: Conservation of biodiversity of Photon Biology: Study Guide for the IB Diploma (SL & HL). Try each question, then compare your working with the full solution.

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Basic practice

Question A1

[1 mark]
A researcher counts the number of different alleles of one gene in a population of a single species. Which level of biodiversity is being measured? (A) Genetic diversity. (B) Species richness. (C) Ecosystem diversity. (D) Species evenness.
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The variety of alleles within one species is genetic diversity (A). Species richness counts species, ecosystem diversity compares habitats, and evenness compares the shares of species.

Final answer

A

Question A2

[1 mark]
Which change is most likely to reduce the biodiversity of a coastal region? (A) Draining a mangrove swamp to build a hotel. (B) Replanting native dune plants after storm damage. (C) Removing an invasive plant from a nature reserve. (D) Banning the collection of coral from a reef.
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Draining a mangrove swamp removes the habitat of many species (A). Replanting, removing an invader and banning collecting all protect or restore biodiversity.

Final answer

A

Question A3

[1 mark]
Which statement about the extinction of the giant moa is supported by the evidence? (A) Climate change was the only cause. (B) Hunting and habitat loss followed the arrival of humans. (C) A disease spread by introduced birds killed them. (D) The last moa died in captive breeding programmes.
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Hunting and destruction of habitat after humans arrived removed the moa (B). Climate change alone, an introduced disease or survival in zoos are not the evidence for this case.

Final answer

B

Question A4

[2 marks]
A woodpecker nests only in holes in large dead trees. (a) Outline how clearing old woodland reduces the woodpecker population. [2]
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Fewer large dead trees means fewer nest holes (1), so fewer pairs can breed and fewer chicks survive (1). Alternatively: the insects living in dead wood are lost (1), so adult survival falls (1).

Final answer

Fewer nest sites, so fewer pairs breed or chicks survive; loss of the insects that live in dead wood lowers food and survival.

Question A5

[1 mark]
Which action is an example of ex situ conservation? (A) Banning logging in a national park. (B) Storing seeds of a rare orchid at low temperature in a seed bank. (C) Reintroducing beavers to a river catchment. (D) Controlling invasive rats on an island reserve.
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Seeds in a bank are kept outside the habitat (B). A logging ban, reintroducing a species to a catchment and controlling invasive rats all protect or restore organisms within their habitat.

Final answer

B

Question A6

[1 mark]
Which conclusion about how many kinds of organism exist is best supported by current evidence? (A) Every living species has now been named. (B) There are probably more species alive now than in the past, and many living species are undescribed. (C) A high present total shows that no mass extinction is under way. (D) The number of named species cannot change.
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Fossil evidence suggests more species now than at any past time, and many living species are still undescribed, so the named total is incomplete (B). A crisis concerns the present rate of loss, not the total.

Final answer

B

Question A7

[2 marks]
The table gives the number of individuals of each animal found in samples from two ponds.\begin{array}{lcccc}\hline \text{Pond}&\text{Beetle}&\text{Snail}&\text{Tadpole}&\text{Newt}\\ \hline \text{P}&\text{9}&\text{9}&\text{9}&\text{0}\\ \hline \text{Q}&\text{20}&\text{5}&\text{2}&\text{1}\\ \hline\end{array} (a) State the species richness of each pond. [1] (b) Identify the pond with the greater evenness. [1]
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(a) Richness is the number of species present: P has 3 (the newt has no individuals) and Q has 4 (1). (b) In P the individuals are shared equally, but in Q the beetle supplies 20 of 28, so P has the greater evenness (1).

Final answer

(a) P 3, Q 4. (b) Pond P.

Question A8

[1 mark]
Which threatened species would be given the highest priority by the EDGE approach? (A) One of 30 close relatives, endangered. (B) The only living member of its family, critically endangered. (C) The only living member of its family, least concern. (D) One of 12 close relatives, least concern.
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EDGE favours species that are both evolutionarily distinct and globally endangered: the only living member of its family and critically endangered (B).

Final answer

B

Question A9

[2 marks]
Seeds of a rare plant are stored in a seed bank. (a) Outline one way in which this contributes to conservation. [2]
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Seeds (germ plasm) are kept alive outside the habitat, so the species is not lost if the wild plants die (1); they can be germinated later to restore or reintroduce populations when the habitat is suitable (1).

Final answer

Seeds kept outside the habitat (1) can be grown to reintroduce plants if wild populations are lost (1).

Question A10

[3 marks]
Fish were counted on three reef sites in 1995 and again in 2015.\begin{array}{lccc}\hline \text{Site}&\text{1}&\text{2}&\text{3}\\ \hline \text{1995}&\text{120}&\text{95}&\text{60}\\ \hline \text{2015}&\text{45}&\text{80}&\text{66}\\ \hline\end{array} (a) Describe the changes between 1995 and 2015, and state which site changed most. [3]
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Fish counts fell at sites 1 and 2 (from 120 to 45 and from 95 to 80) (1) and rose slightly at site 3 (from 60 to 66) (1). The decrease was greatest at site 1, a fall of 75, or 63\% (1).

Final answer

Site 1 fell by 75 (63%), site 2 by 15, site 3 rose by 6; the fall is much greater at site 1.

Tutorial practice

Question B1

[4 marks]
A tropical forest is being converted to an oil-palm plantation, and a new road crosses what remains. (a) Explain two ways in which these changes reduce the biodiversity of the forest. [4]
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Any two pairs: clearing removes the trees that provide food and shelter (1), so species that depend on them decline or disappear (1); the road splits the forest into fragments (1), so populations become small and isolated and are more likely to die out (1); the road gives hunters access, so animals are over-exploited (1) and numbers fall below the level at which they recover (1).

Final answer

Clearing removes habitat and food so species are lost; the road fragments the forest into small isolated populations and gives hunters access.

Question B2

[4 marks]
Humans have caused the extinction of species at different times. (a) State one species that has been made extinct by human activity and name the activity responsible. [2] (b) Explain how that activity led to the extinction. [2]
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(a) A named species, such as the giant moa (1), with the activity: hunting and habitat destruction after human arrival (1). Alternatively the Caribbean monk seal, with hunting and overfishing. (b) Hunting killed adults faster than the population could reproduce (1); the numbers kept falling until no breeding individuals were left (1).

Final answer

(a) Moa; hunting and habitat destruction (or monk seal; hunting and overfishing). (b) Adults removed faster than replaced, no breeding, numbers fall to zero.

Question B3

[4 marks]
Farmland has split a forest into small fragments. A forest mammal needs a large territory. (a) Explain how fragmentation could reduce the survival of the mammal population. [2] (b) Suggest one measure that would reduce the effect, and explain how it works. [2]
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(a) Each fragment is too small for a territory, so fewer individuals can live there (1); the populations become small and isolated, so mates are harder to find and the population is more likely to die out (1). (b) Plant or protect a corridor of forest between the fragments (1) so animals can move between them, find mates and recolonise a fragment if the local population dies out (1).

Final answer

(a) Smaller range, fewer individuals, isolation, lower breeding. (b) A corridor of trees linking fragments.

Question B4

[4 marks]
A zoo breeds a critically endangered frog. The marsh where it lived is being drained. (a) Identify the type of conservation and give a reason. [1] (b) Outline two ways the programme can help conserve the species. [2] (c) State one limitation of this approach. [1]
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(a) Ex situ, because the frogs are kept outside their natural habitat (1). (b) Any two: the breeding stock survives even if the wild population is lost (1); offspring can be released when a suitable habitat is restored (1); the zoo can maintain genetic diversity by choosing mates (1). (c) One limitation: the drainage that endangered the frog is not stopped, or the captive population has a small gene pool (1). Maximum 4.

Final answer

(a) Ex situ: kept outside its habitat. (b) Insurance population; release when habitat restored. (c) The threat to the habitat remains; small gene pool.

Question B5

[6 marks]
A rare orchid can be protected in a nature reserve or by storing its seeds in a seed bank. (a) Compare the advantages and limitations of the two approaches. [6]
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Reserve (in situ): protects the whole habitat, including pollinators and soil fungi, so the orchid keeps its interactions (1); the orchid can keep evolving with changing conditions (1); needs money, staff and enforcement against poaching or clearing (1). Seed bank (ex situ): stores many seeds in little space at a low cost (1); the seeds are safe from habitat destruction and can be sown later (1); it does not protect the habitat or interactions, so plants grown later need a suitable site (1). A balanced conclusion that uses both can replace one point. Maximum 6.

Final answer

Reserve: keeps habitat, pollinators and interactions, but needs funding and enforcement. Seed bank: cheap, safe from habitat loss, but habitat and interactions lost. Conclude: use both.

Question B6

[4 marks]
Three threats act on a protected forest. \begin{array}{ll}\hline \text{Threat}&\text{Effect}\\ \hline \text{1. Poaching of a large cat}&\text{Adults killed}\\ \hline \text{2. An invasive shrub}&\text{Shades out native seedlings}\\ \hline \text{3. Farmland on all sides}&\text{Isolated patches}\\ \hline\end{array} (a) Suggest one management action for each threat. [3] (b) Explain how one of your actions helps the species concerned. [1]
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(a) Threat 1: ranger patrols and penalties (1); threat 2: remove the shrub and monitor for regrowth (1); threat 3: corridors between patches or a buffer zone (1). (b) The action must say why it works, for example: a corridor lets individuals move between patches, so populations are connected and can breed and recolonise (1).

Final answer

(a) 1 patrols/enforcement; 2 remove shrub; 3 corridors. (b) Corridor lets animals move and breed between patches.

Question B7

[5 marks]
Individuals of each tree species were counted in two forest plots of equal area.\begin{array}{lccccc}\hline \text{Species}&\text{1}&\text{2}&\text{3}&\text{4}&\text{5}\\ \hline \text{Plot 1}&\text{12}&\text{8}&\text{5}&\text{3}&\text{2}\\ \hline \text{Plot 2}&\text{24}&\text{3}&\text{1}&\text{1}&\text{1}\\ \hline\end{array} (a) State the species richness of each plot. [1] (b) Calculate Simpson's reciprocal index for each plot. [2] (c) Compare the species diversity of the two plots. [2]
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(a) Richness is 5 in both plots (1). (b) N=30 in each plot, so N(N-1)=870. Plot 1: \sum n(n-1)=132+56+20+6+2=216, so D=870/216=4.0 (1). Plot 2: \sum n(n-1)=552+6+0+0+0=558, so D=870/558=1.6 (1). (c) Richness is the same (1), but plot 1 has the higher D because its individuals are shared more evenly, while one species dominates plot 2 (1).

Final answer

(a) 5 and 5. (b) Plot 1: 4.0; plot 2: 1.6. (c) Same richness; plot 1 has higher D, so is more even and more diverse.

Question B8

[4 marks]
Wading birds were surveyed on two wetlands in 2000 and 2020, using the same method.\begin{array}{lcccc}\hline \text{Wetland}&\text{Birds 2000}&\text{Birds 2020}&\text{Species 2000}&\text{Species 2020}\\ \hline \text{Protected}&\text{410}&\text{455}&\text{13}&\text{13}\\ \hline \text{Drained}&\text{380}&\text{150}&\text{14}&\text{9}\\ \hline\end{array} (a) Calculate the percentage change in the number of birds on the drained wetland. [1] (b) Compare the changes on the two wetlands. [3]
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(a) (150-380)/380\times100=-61\% (1). (b) The protected wetland gained birds (410 to 455, about +11\%) and kept its richness at 13 species (1); the drained wetland lost birds and species (from 14 to 9) (1); the fall in the drained site is much larger, which is consistent with loss of habitat (1).

Final answer

(a) -61\%. (b) Protected: more birds, same richness; drained: birds and species both fell.

Question B9

[5 marks]
A corridor of native shrubs was planted in 2015 between ten forest patches. A small mammal was surveyed in these linked patches and in ten similar patches that were not linked. The table gives the percentage of patches occupied.\begin{array}{lccc}\hline \text{Patches}&\text{2014}&\text{2018}&\text{2022}\\ \hline \text{Linked}&\text{40}&\text{68}&\text{71}\\ \hline \text{Not linked}&\text{42}&\text{44}&\text{41}\\ \hline\end{array} (a) Calculate the increase in occupancy of the linked patches between 2014 and 2022. [1] (b) Explain why unlinked patches were also surveyed. [2] (c) Evaluate the claim that the corridor increased the survival of the mammal. [2]
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(a) 71-40=31 percentage points, or 31/40\times100=78\% (1). (b) The unlinked patches are a control (1): they show what happens without a corridor, so changes caused by weather or a region-wide trend would appear in both sets (1). (c) Occupancy rose in linked patches and stayed near 42\% in the unlinked ones, which supports the claim that the corridor helped (1). Limits: only one species and ten patches each, and the other differences between patches are not known, so repeat the study in other regions (1).

Final answer

(a) 31 percentage points (78%). (b) Control for weather, climate, general trend. (c) Supports; one study, small sample, other factors.

Question B10

[6 marks]
A wetland on the edge of a city is proposed as a site for housing. (a) Justify the conservation of the wetland, giving different kinds of reason and acknowledging one cost. [6]
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Ecological: the wetland supports food webs, stores flood water and filters pollutants, services that a built site loses (1) plus a biological consequence, for example fewer species or nursery habitat (1). Economic and human: fishing, tourism or education provide income and livelihoods (1) and a named benefit to the residents (1). Ethical or cultural: species have a right to exist and the site has value for future generations (1). A cost is acknowledged, such as the need for housing, and a reasoned choice is made, for example building on degraded land instead (1).

Final answer

Ecological (food web, flood and water purification); economic (fishing, tourism); ethical (existence value); cost acknowledged.

Advanced practice

Question C1

[6 marks]
A hypothesis states that traffic noise from a new road reduces the number of frog species in nearby ponds. The graph shows the number of frog species in five ponds at different distances from the road. [Graph: scatter graph of frog species per pond against distance from road] (a) Describe the relationship shown. [2] (b) Explain how far the data support the hypothesis. [2] (c) Suggest an improvement to the investigation. [2]
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(a) Species number rises as distance increases (1), from 2 at 50 m to 6 at 600 m, and does not change between 600 and 900 m (1). (b) The pattern is consistent with the hypothesis (1) but it is a correlation, and it does not show noise is the cause (1). (c) Other factors may differ, such as pond area, water quality or surrounding vegetation, so compare ponds of the same size and water quality (1) or compare the same ponds before and after the road opened, with measurements of noise (1).

Final answer

(a) Species rise with distance, from 2 at 50 m to 6 at 600 m and beyond. (b) Supports; correlation only. (c) Control for pond area, water quality; before-and-after.

Question C2

[5 marks]
Four threatened species of one group are being considered for a conservation programme. \begin{array}{lll}\hline \text{Species}&\text{Relatives}&\text{Red List category}\\ \hline \text{A}&\text{only living member of its order}&\text{critically endangered}\\ \hline \text{B}&\text{one of 40 similar species in its genus}&\text{critically endangered}\\ \hline \text{C}&\text{only living member of its family}&\text{vulnerable}\\ \hline \text{D}&\text{one of 12 species in its genus}&\text{endangered}\\ \hline\end{array} (a) Identify the species to conserve first and justify the choice using both EDGE criteria. [3] (b) Suggest why B may rank below A even though both are critically endangered. [1] (c) State one other consideration that conservation managers must weigh. [1]
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(a) Species A should be first (1): it is the most distinct, so the loss of its lineage would remove the most unique evolutionary history (1), and it is also at the highest risk of extinction (1). (b) B has the same risk as A but 39 close relatives, so its loss removes much less unique evolutionary history (1). (c) One practical or ethical point, for example the cost per species, or whether the same habitat protection also saves other species (1).

Final answer

(a) A: most distinct and highest risk. (b) B has many close relatives, so little unique history is lost. (c) Cost, or benefit to other species.

Question C3

[5 marks]
Volunteers record sightings of a woodland butterfly with a phone app. In 2012, 15 volunteers made 120 records. In 2022, 300 volunteers made 960 records. (a) Calculate the number of records per volunteer in each year. [2] (b) Evaluate whether the records show that the butterfly population has increased. [3]
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(a) 120/15=8 records per volunteer in 2012 (1) and 960/300=3.2 in 2022 (1). (b) The total rose eightfold, but the number of volunteers rose twentyfold, so the effort changed and the rise does not show more butterflies (1). Records per volunteer fell, which could mean the butterfly became rarer (1), although volunteers may also visit different, easier sites; a standard survey with the same routes and times is needed (1).

Final answer

(a) 8 and 3.2 records per volunteer. (b) More records, but more observers and fewer per observer; effort not standardised, sites biased.

Question C4

[5 marks]
A seed bank will store seeds of a rare tree that survives in six small populations. Collection X holds 100 seeds from one tree. Collection Y holds 10 seeds from each of 10 trees in each of three populations. (a) Identify which collection is more useful for conservation and explain why. [2] (b) State one reason for including several populations. [1] (c) Outline two limitations of conserving the tree in a seed bank. [2]
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(a) Collection Y (1), because it contains seeds from many parent trees and from different populations, so it holds more of the alleles of the species (1). (b) A more diverse stock lets reintroduced populations adapt to changing conditions (1). (c) The seeds do not save the habitat, so reintroduction needs a suitable site (1); stored seeds lose viability over time, so they must be germinated and replaced (1).

Final answer

(a) Y: alleles from many trees and populations. (b) Different alleles, adapt. (c) Habitat not saved; seeds lose viability.

Question C5

[6 marks]
A quarry was reclaimed in 2010 by spreading topsoil and planting native trees. Plant species were counted on the reclaimed site, on an unreclaimed part of the quarry and in the nearby natural woodland.\begin{array}{lccc}\hline \text{Years after 2010}&\text{2}&\text{6}&\text{12}\\ \hline \text{Reclaimed site}&\text{3}&\text{9}&\text{21}\\ \hline \text{Unreclaimed quarry}&\text{2}&\text{3}&\text{4}\\ \hline \text{Natural woodland}&\text{28}&\text{28}&\text{29}\\ \hline\end{array} (a) Calculate the mean rate of increase in species on the reclaimed site between years 2 and 12. [1] (b) Evaluate the success of the reclamation. [3] (c) Suggest two further measurements needed to judge the recovery. [2]
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(a) (21-3)/(12-2)=1.8 species per year (1). (b) The reclaimed site rose from 3 to 21 species, while the unreclaimed quarry reached 4, so reclamation increased richness (1); it reached 21/29=72\% of the natural woodland, so recovery is incomplete (1) but still rising (1). (c) Any two: count evenness or the abundance of each species (1); record animals and not only plants (1); check that the species are native and not invasive, or monitor for longer (1). Maximum 6.

Final answer

(a) 1.8 species per year. (b) Reclamation worked: 21 vs 4; 72% of the woodland. (c) Evenness, animals, native species, longer period.

Connected questions

Question X1

Connected questions[8 marks]
A4.2 + A4.1. Logging has left a rare forest mammal in two fragments, 40 km apart. Each holds about 12 individuals. (a) Explain how genetic diversity of the population is likely to fall. [3] (b) Explain how long isolation could lead to the formation of new species. [3] (c) Suggest one conservation measure that would reduce the problem in (a), and state how it would affect the process in (b). [2]
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(a) In a small population, chance changes in allele frequency (genetic drift) are large (1); some alleles are lost (1); related animals mate, so harmful recessive alleles are expressed and survival falls (1). (b) The fragments have no gene flow (1); if conditions differ, selection favours different alleles in each (1); after long isolation the populations may become unable to interbreed, so a new species forms (1). (c) A corridor, or moving animals between fragments (translocation), restores gene flow and raises genetic diversity (1); the cost is that the two populations are no longer separate (1).

Final answer

(a) Small population: drift, inbreeding, less diversity. (b) Isolation, different selection, no gene flow, reproductive barriers. (c) Corridor or translocation.

Question X2

Connected questions[7 marks]
A4.2 + C4.1. A reserve manager estimates a population of a rare skink by capture and recapture. In the first sample 35 skinks were marked and released. In the second sample 28 were caught and 7 of them were marked. Five years later the estimate was 98. (a) Calculate the population estimate from the first two samples. [2] (b) State two assumptions of this method. [2] (c) Calculate the percentage change in the estimate and evaluate whether the population is declining. [3]
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(a) N=35\times28/7=140 (1) skinks (1). (b) Any two: marked individuals mix at random with the rest (1); no births, deaths or movement in or out between the samples (1); the marks stay visible and do not change survival (1). (c) (98-140)/140\times100=-30\% (1). A fall of this size could show that the population is declining, but the same method and effort must be used each time (1), and two estimates cannot show a trend, so repeated surveys are needed (1). Maximum 7.

Final answer

(a) 140. (b) Marked mix randomly; no migration or deaths; marks stay. (c) -30\%; fall of 30%; need the same method; more surveys.

Question X3

Connected questions[6 marks]
A4.2 + D4.2. A large predator was reintroduced to a reserve. Deer density fell from 18 to 9 per km^2 over eight years, and sapling survival in the forest rose. (a) Calculate the percentage change in deer density. [1] (b) Explain how the reintroduction could increase plant biodiversity. [3] (c) Explain why this is classified as rewilding and how it affects the stability of the community. [2]
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(a) (9-18)/18\times100=-50\% (1). (b) The predator kills deer (1); fewer deer browse saplings, so more saplings survive and grow (1); the extra trees provide food and habitat for other species, which raises biodiversity (1). (c) This is rewilding, because a lost species is restored (1) which brings back a feeding interaction that regulates the community and helps it to return to stability after disturbance (1).

Final answer

(a) -50\%. (b) Fewer deer browse saplings, so more survive; trees grow. (c) Rewilding; restores a lost interaction and the stability of the community.

From the book

Photon Biology: Study Guide for the IB Diploma (SL & HL)

Conservation of biodiversity from the core ideas to full exam questions, with question types, worked examples and graded practice.

About the book